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What will be the output of the following code?
int[] array = {2, 4, 6, 8, 10};
int target = 5;
int count = 0;
for (int i = 0; i < array.length; i++) {
    if (array[i] % 2 == 0) {
        count++;
    }
}
System.out.println(count);
  • a)
    0
  • b)
    1
  • c)
    2
  • d)
    5
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following code?int[] array = {2, 4, 6, ...
Understanding the Code
The given code initializes an integer array and counts how many elements are even. Let's break it down:
Code Breakdown
- Array Initialization:
java
int[] array = {2, 4, 6, 8, 10};
This creates an array containing five even numbers: 2, 4, 6, 8, and 10.
- Target and Count Variables:
java
int target = 5;
int count = 0;
Here, `target` is initialized but not used in the logic. `count` is initialized to zero to keep track of even numbers.
- Looping Through the Array:
java
for (int i = 0; i < array.length;="" i++)="" />
This loop iterates through each index of the array.
- Even Number Check:
java
if (array[i] % 2 == 0) {
count++;
}
The condition checks if the current array element is even (i.e., divisible by 2). If true, it increments the `count`.
Final Count Calculation
- Since all elements in the array (2, 4, 6, 8, 10) are even, the `count` will increment for each of the five iterations.
Output Result
- After the loop completes, `count` equals 5. Therefore, when the program executes `System.out.println(count);`, it prints 5.
Correct Answer
- The correct answer to the output of the code is option d) 5. The initial assertion of option "C" being correct is incorrect.
Free Test
Community Answer
What will be the output of the following code?int[] array = {2, 4, 6, ...
The code counts the number of even numbers in the 'array'. It initializes a counter variable 'count' with 0 and iterates through each element of the array. If an element is divisible by 2 (i.e., even), the counter is incremented. The final count is printed, which is 2.
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